我正在尝试调试分配的一部分代码(我对 Java 还是很陌生)并且已经梳理了许多资源来解决这个冲突,但仍然不能完全解决.
I'm trying to debug a portion of code for an assignment (I'm still very new to Java) and have combed through many resources to solve this conflict but still can't quite work it out.
public static void main(String [] args){
Scanner keyboard = new Scanner(System.in);
String input = null;
do
{
System.out.println("Enter 'A' for option A or 'B' for option B.");
String input = keyboard.next();
input.toLowerCase();
input.charAt(0);
}
while ((input != "a") || (input != "b"));
}
输入字符串总是出现重复的局部变量错误.
I always get a Duplicate Local Variable error with the input String.
任何帮助将不胜感激!
替换
String input = keyboard.next();
与
input = keyboard.next();
如果你在变量名之前放置一个String,它就是一个声明.而且你只能在一个范围内声明一个变量名.
If you put a String before the variable name it is a declaration. And you can declare a variable name only once in a scope.
这篇关于Java 错误,重复的局部变量的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!
Java从数组中删除重复项?Java Remove Duplicates from an Array?(Java从数组中删除重复项?)
如何修复调用失败来自服务器的意外响应:在 AnHow to fix Invocation failed Unexpected Response from Server: Unauthorized in Android studio(如何修复调用失败来自服务器的意外响应:在
AES 加密,解密文件中有多余的垃圾字符AES encryption, got extra trash characters in decrypted file(AES 加密,解密文件中有多余的垃圾字符)
AES 错误:给定的最终块未正确填充AES Error: Given final block not properly padded(AES 错误:给定的最终块未正确填充)
在 JAVA 中使用 AES/GCM 检测不正确的密钥Detecting incorrect key using AES/GCM in JAVA(在 JAVA 中使用 AES/GCM 检测不正确的密钥)
Java 中的 AES-256-CBCAES-256-CBC in Java(Java 中的 AES-256-CBC)