您能否解释一下来自 HashMap 构造函数 特别是这一行
Can you please explain this code snippet from HashMap constructor specifically the line
容量<<= 1:
capacity <<= 1:
// Find a power of 2 >= initialCapacity
198 int capacity = 1;
199 while (capacity < initialCapacity)
200 capacity <<= 1;
相当于capacity = capacity <<<1;
.
该操作将容量的位向左移动一位,相当于乘以 2.
It is equivalent to capacity = capacity << 1;
.
That operation shifts capacity's bits one position to the left, which is equivalent to multiplying by 2.
您发布的特定代码找到大于 initialCapacity
的 2 的最小幂.
The specific code you posted finds the smallest power of 2 which is larger than initialCapacity
.
所以如果 initialCapacity
为 27,例如 capacity
在循环后将是 32 (2^5).
So if initialCapacity
is 27, for example, capacity
will be 32 (2^5) after the loop.
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