我正在尝试更新列 visited
以赋予它值 1.我使用 MySQL 工作台,并且我正在从工作台内部在 SQL 编辑器中编写语句.我正在编写以下命令:
I'm trying to update the column visited
to give it the value 1. I use MySQL workbench, and I'm writing the statement in the SQL editor from inside the workbench. I'm writing the following command:
UPDATE tablename SET columnname=1;
它给了我以下错误:
您正在使用安全更新模式并且您尝试在没有使用 KEY 列的 WHERE 要禁用安全模式,请切换选项....
You are using safe update mode and you tried to update a table without a WHERE that uses a KEY column To disable safe mode, toggle the option ....
我按照说明操作,从 Edit
菜单中取消选中 safe update
选项,然后取消选中 Preferences
和 SQL Editor
代码>.同样的错误仍然出现&我无法更新此值.请告诉我怎么了?
I followed the instructions, and I unchecked the safe update
option from the Edit
menu then Preferences
then SQL Editor
. The same error still appear & I'm not able to update this value. Please, tell me what is wrong?
我找到了答案.问题是我必须在表名之前加上模式名.即,命令应该是:
I found the answer. The problem was that I have to precede the table name with the schema name. i.e, the command should be:
UPDATE schemaname.tablename SET columnname=1;
谢谢大家.
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