在 SQL Server XPath 中获取跟随兄弟

问题描述

由于 SQL Server 不支持跟随兄弟轴 - 获得它的最佳方法是什么?假设我有这样的 XML，我想在匹配值 'dog' 的节点之后获取第一个 'b' 节点:

Since SQL Server does not support following-sibling axis - what is the best way to get it? Let's say I have XML like this and I would like to get the first 'b' node after a node matching the value 'dog':

<root>
    <a>cat</a>
    <b>Cats don't like milk</b>
    <a>dog</a>
    <b>Dogs like everything</b>
</root>

推荐答案

你可以尝试这样的事情.

You could try something like this.

declare @X xml = '
<root>
    <a>cat</a>
    <b>Cats don''t like milk</b>
    <a>dog</a>
    <c>not this</c>
    <b>Dogs like everything</b>
    <b>and not this</b>
</root>'

select @X.query('(/root/b[. >> (/root/a[. = "dog"])[1]])[1]')

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