我正在尝试制作一个包含多个页面"的顶点表单,以便我可以实现漂亮的布局.
I'm trying to make an apex form that has multiple 'pages' within it, so that I can achieve a nice layout.
例如:第 1 页 - 个人详细信息 >> 第 2 页 - 职业 >> 第 3 页 - 职业历史 >> 提交
For example: Page 1 - Personal Details >> Page 2 - Occupation >> Page 3 - Career History >> Submit
有没有办法在不提交一页的情况下做到这一点,因为这会扰乱我对表格条目的验证.
Is there a way to do this without submitting one page at a time as this would mess up my validation for the table entry.
这是一个广泛的问题 - 有很多可能的解决方案.您需要在页面上创建多个区域,以便无需提交页面即可轻松显示或隐藏不同的页面项目集.
It's kind of a broad question - lots of possible solutions. You will need to create several regions on the page, so that you can easily show or hide different sets of page items without submitting the page.
如果您只是想保持页面整洁,您可以使用 Hide and Show Region 模板,或者您可以创建一个 Region Display Selector 区域.
If you simply want to keep the page tidy, you could make use of the Hide and Show Region template, or you could create a Region Display Selector region.
为了改善用户体验,我可能会这样做:
To help the user experience flow a bit better, I would probably do something like this:
Personal Details、Occupation 和 Career History.Personal Details、Next 和 Previous 按钮中的 Next 按钮在 Occupation 中,以及 Career History 中的 Previous 和 Submit.Submit 按钮当然是提交页面.Next 和 Previous 按钮会根据需要显示和隐藏区域.Personal Details, Occupation, and Career History.Next button in Personal Details, Next and Previous buttons in Occupation, and Previous and Submit in Career History.Submit button submits the page of course. The Next and Previous buttons show and hide the regions as appropriate.这篇关于创建包含多个页面的 Apex 表单的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!
如何将“2016-07-01 01:12:22 PM"转换为“2016-07-0How to convert #39;2016-07-01 01:12:22 PM#39; to #39;2016-07-01 13:12:22#39; hour format?(如何将“2016-07-01 01:12:22 PM转换为“2016-07-01 13:1
UNPIVOT 在多列上返回多列UNPIVOT on multiple columns to return multiple columns(UNPIVOT 在多列上返回多列)
Oracle UNPIVOT 和 SYSDATE 给出奇怪的结果Oracle UNPIVOT and SYSDATE giving weird results(Oracle UNPIVOT 和 SYSDATE 给出奇怪的结果)
如何在 Oracle PLSQL 中透视表?How to pivot a table in Oracle PLSQL?(如何在 Oracle PLSQL 中透视表?)
将列转为行(oracle)Unpivot columns into rows (oracle)(将列转为行(oracle))
将 Oracle DATE 转换为 Unix 风格的时间(自 1906 年以来Convert Oracle DATE to Unix-style time (seconds since 1906?)(将 Oracle DATE 转换为 Unix 风格的时间(自 1906 年以来的秒数?))