SQL - 总行数的百分比

时间:2023-02-22
本文介绍了SQL - 总行数的百分比的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有这个查询:

SELECT 
Count(*) as Cnt, 
Category
FROM [MyDb].[dbo].[MyTable]
group by Category
order by Cnt

它为我提供了每个 Category 中的行数.现在我想添加第三列,它会给我 Cnt/(此表中的总行数).

It gives me count of rows in each Category. Now I would like to add a third column that would give me Cnt / (total rows in this table).

我该怎么做?

推荐答案

你可以用子查询来做到:

you could do it with a subquery:

SELECT Count(*) as Cnt, Category, 
  (Cast(Count(*) as real) / cast((SELECT Count(*) FROM [MyDb].[dbo].[MyTable]) as  real)) AS [Percentage]
FROM [MyDb].[dbo].[MyTable]
group by Category
order by Cnt

或使用变量:

declare @total real;
select @total = count(*) from [MyDb].[dbo].[MyTable];

SELECT Count(*) as Cnt, Category, (Cast(Count(*) as real) / @total) AS [Percentage]
FROM [MyDb].[dbo].[MyTable]
group by Category
order by Cnt

我在两个示例中都将 count(*) 转换为实数以避免整数除法类型问题.

I've cast count(*) as real in both examples to avoid integer-division type issues.

希望这有帮助约翰

这篇关于SQL - 总行数的百分比的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!

上一篇:如何从在线 CSV 插入 SQL Server 数据库数据? 下一篇:从 XML 字段中选择 XML 字段 = X

相关文章

最新文章