使用 MongoDB 和 C# 使用 FindOne() 时,是否可以忽略对象中未找到的字段?
When using a FindOne() using MongoDB and C#, is there a way to ignore fields not found in the object?
EG,示例模型.
public class UserModel
{
public ObjectId id { get; set; }
public string Email { get; set; }
}
现在我们也在 MongoDB 集合中存储了一个密码,但不想将其绑定到上面的 out 对象.当我们像这样执行 Get 时,
Now we also store a password in the MongoDB collection, but do not want to bind it to out object above. When we do a Get like so,
var query = Query<UserModel>.EQ(e => e.Email, model.Email);
var entity = usersCollection.FindOne(query);
我们收到以下错误
Element 'Password' does not match any field or property of class
无论如何要告诉 Mongo 忽略它无法与模型匹配的字段?
Is there anyway to tell Mongo to ignore fields it cant match with the models?
是的.只需使用 BsonIgnoreExtraElements
属性装饰您的 UserModel
类:
Yes. Just decorate your UserModel
class with the BsonIgnoreExtraElements
attribute:
[BsonIgnoreExtraElements]
public class UserModel
{
public ObjectId id { get; set; }
public string Email { get; set; }
}
顾名思义,驱动程序会忽略任何额外的字段而不是抛出异常.更多信息在这里 - 忽略额外元素.
As the name suggests, the driver would ignore any extra fields instead of throwing an exception. More information here - Ignoring Extra Elements.
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