我用以下方式编写了一个单例 C++:
I write a singleton c++ in the follow way:
class A {
private:
static A* m_pA;
A();
virtual ~A();
public:
static A* GetInstance();
static void FreeInstance();
void WORK1();
void WORK2();
void WORK3();
}
}
A* A::GetInstance() {
if (m_pA == NULL)
m_pA = new A();
return m_pA;
}
A::~A() {
FreeInstance() // Can I write this? are there any potential error?
}
void A::FreeInstance() {
delete m_pA;
m_pA = NULL;
}
谢谢!Evan Teran 和 sep61.myopenid.com 的回答是正确的,而且非常好!我的方法是错误的,我希望任何编写这样代码的人都可以避免我的愚蠢错误.
Thanks! Evan Teran and sep61.myopenid.com 's answer is right, and really good! My way is wrong, I wish any one writting such code can avoid my silly mistake.
我的项目中的单例A有一个智能指针向量,另一个线程也可以编辑这个向量,所以当应用程序关闭时,即使我添加了很多CMutex,它也会变得不稳定.多线程错误 + 单例错误浪费了我 1 天时间.
//-----------------------------------------------------------一个新的单例,如果您认为以下示例有问题,欢迎您
My singleton A in my project has a vector of smart pointer, and another thread can also edit this vector, so when the application is closing, it always become unstable even I add lots of CMutex. Multithread error + singleton error wasted me 1 day.
//----------------------------------------------------------- A new singleton, you are welcome to edit if you think there is any problem in the following sample:
class A {
private:
static A* m_pA;
explicit A();
void A(const A& a);
void A(A &a);
const A& operator=(const A& a);
virtual ~A();
public:
static A* GetInstance();
static void FreeInstance();
void WORK1();
void WORK2();
void WORK3();
}
}
A* A::GetInstance() {
if (m_pA == NULL){
static A self;
m_pA = &self;
}
return m_pA;
}
A::~A() {
}
您可以使用像这样的静态对象来避免删除它:
You can avoid needing to delete it by using a static object like this:
if(m_pA == 0) {
static A static_instance;
m_pA = &static_instance;
}
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