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        如何在 C++ 中将窗口的屏幕截图作为位图对象获取

        时间:2023-10-06

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                • 本文介绍了如何在 C++ 中将窗口的屏幕截图作为位图对象获取?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

                  问题描述

                  如何在 C++ 中将窗口的屏幕截图作为位图对象获取?假设我已经有了窗口句柄.我还想知道是否可以在窗口处于最小化状态时获取屏幕截图?

                  How to get screenshot of a window as bitmap object in C++? Supposed that I already have the window handle. And I want to know also whether it's possible to get the screenshot of a window when it's in minimized state?

                  这里的 C++ 是指 VC++ 以及与 Windows XP+ (win32) 相关的所有库.

                  C++ here means VC++ with all the libraries associated with Windows XP+ (win32).

                  推荐答案

                  你应该调用 PrintWindow API:

                  you should call the PrintWindow API:

                  void CScreenShotDlg::OnPaint()
                  {
                      // device context for painting
                      CPaintDC dc(this);
                  
                      // Get the window handle of calculator application.
                      HWND hWnd = ::FindWindow( 0, _T( "Calculator" ));
                  
                      // Take screenshot.
                      PrintWindow( hWnd,
                                   dc.GetSafeHdc(),
                                   0 );
                  }
                  

                  看到这个问题:获取窗口截图windows API

                  如果你不使用 MFC,这里是纯 PrintWindow 签名:

                  if you are not using MFC, here the pure PrintWindow signature:

                  BOOL PrintWindow(
                      HWND hwnd,
                      HDC hdcBlt,
                      UINT nFlags
                  );
                  

                  有关更多详细信息,请参阅 MSDN:http:///msdn.microsoft.com/en-us/library/dd162869(v=vs.85).aspx

                  see MSDN for more details: http://msdn.microsoft.com/en-us/library/dd162869(v=vs.85).aspx

                  关于如何像Matteo所说的那样将其保存为位图取决于您使用的实际框架...

                  about how to save it as bitmap asMatteo said depends on the actual framework you are using...

                  这里是原始 C++ 中的完整示例

                  here full example in raw C++

                  #define _WIN32_WINNT    0x0501        //xp
                  #include <windows.h>
                  
                  int main()
                  { 
                      RECT rc;
                      HWND hwnd = FindWindow(TEXT("Notepad"), NULL);    //the window can't be min
                      if (hwnd == NULL)
                      {
                          cout << "it can't find any 'note' window" << endl;
                          return 0;
                      }
                      GetClientRect(hwnd, &rc);
                  
                      //create
                      HDC hdcScreen = GetDC(NULL);
                      HDC hdc = CreateCompatibleDC(hdcScreen);
                      HBITMAP hbmp = CreateCompatibleBitmap(hdcScreen, 
                          rc.right - rc.left, rc.bottom - rc.top);
                      SelectObject(hdc, hbmp);
                  
                      //Print to memory hdc
                      PrintWindow(hwnd, hdc, PW_CLIENTONLY);
                  
                      //copy to clipboard
                      OpenClipboard(NULL);
                      EmptyClipboard();
                      SetClipboardData(CF_BITMAP, hbmp);
                      CloseClipboard();
                  
                      //release
                      DeleteDC(hdc);
                      DeleteObject(hbmp);
                      ReleaseDC(NULL, hdcScreen);
                  
                      cout << "success copy to clipboard, please paste it to the 'mspaint'" << endl;
                  
                      return 0;
                  }
                  

                  这篇关于如何在 C++ 中将窗口的屏幕截图作为位图对象获取?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!

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