如何将 push_back
struct
转化为向量?
How can I push_back
a struct
into a vector?
struct point {
int x;
int y;
};
std::vector<point> a;
a.push_back( ??? );
point mypoint = {0, 1};
a.push_back(mypoint);
或者如果你被允许,给 point
一个构造函数,这样你就可以使用一个临时的:
Or if you're allowed, give point
a constructor, so that you can use a temporary:
a.push_back(point(0,1));
如果你在一个用struct
声明的类中放置一个构造函数,有些人会反对,这使它成为非POD,也许你无法控制point的定义代码>.因此,您可能无法使用此选项.但是,您可以编写一个提供相同便利的函数:
Some people will object if you put a constructor in a class declared with struct
, and it makes it non-POD, and maybe you aren't in control of the definition of point
. So this option might not be available to you. However, you can write a function which provides the same convenience:
point make_point(int x, int y) {
point mypoint = {x, y};
return mypoint;
}
a.push_back(make_point(0, 1));
这篇关于如何将 vector::push_back()` 与结构一起使用?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!