我正在用 C++ 读取 CSV 文件,行格式如下:
I'm reading a CSV file in C++ and the row format is as such:
小学,中学,第三",主要",,中学",18, 4, 0, 0, 0
"Primary, Secondary, Third", "Primary", , "Secondary", 18, 4, 0, 0, 0
(注意空值)
当我这样做时:
while (std::getline(ss, csvElement, ',')) {
csvColumn.push_back(csvElement);
}
这会将第一个字符串分成不正确的部分.
This splits up the first string into pieces which isn't correct.
如何在迭代时保留字符串?我尝试将上述方法结合起来,同时还抓取了由双引号分隔的行,但我得到了疯狂的结果.
How do I preserve the string when iterating? I tried to do a combination of the above and while also grabbing the lines separated by double quote but I got wild results.
您需要根据是否在引号之间来解释逗号.这对于 getline()
来说太复杂了.
You need to interpret the comma depending on whether you're betwwen the quote or not. This is too complexfor getline()
.
解决方案是使用 getline()
读取整行,并通过逐个字符遍历字符串来解析该行,并维护一个指示符是否在双引号之间.
The solution would be to read the full line with getline()
, and parse the line by iterating through the string character by character, and maintaing an indicator whether you're between double quotes or not.
这是第一个原始"示例(未删除字段中的双引号且不解释转义字符):
Here is a first "raw" example (double quotes are not removed in the fields and escape characters are not interpreted):
string line;
while (std::getline(cin, line)) { // read full line
const char *mystart=line.c_str(); // prepare to parse the line - start is position of begin of field
bool instring{false};
for (const char* p=mystart; *p; p++) { // iterate through the string
if (*p=='"') // toggle flag if we're btw double quote
instring = !instring;
else if (*p==',' && !instring) { // if comma OUTSIDE double quote
csvColumn.push_back(string(mystart,p-mystart)); // keep the field
mystart=p+1; // and start parsing next one
}
}
csvColumn.push_back(string(mystart)); // last field delimited by end of line instead of comma
}
在线演示
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